A model rocket flies horizontally off the edge of a cliff at a velocity of 50.0 m/s. If

A model rocket flies horizontally off the edge of a cliff at a velocity of 50.0 m/s. If the canyon below is 100.0 m deep, how far from the edge of the cliff does the model rocket land?
My teacher provided the equations:
x= vt and y = (Vi * t)1/2* a * t^2